For those who were curious why these could both work, note that `(A && B) || C` differs from `A && (B || C)` in two cases: when `A` is false, `C` is true, and `B` is any value.

But in this case in particular, those differences would create a bug when `A` is false (the year is not divisible by 4) at the same time that `C` is true (the year is divisible by 400). Since that can't happen, the bug cannot occur.